Question

Small quantities of solution of compounds $TX,TY$ and $TZ$ are put into separate test tubes containing $X,Y$ and $Z$ solution. $TX$ does not react with any of these. $TY$ reacts both with $X$ and $Z.TZ$ reacts with $X$. The decreasing order of ease of oxidation of the anions $X^{-}$, $Y^{-}$ and $Z^{-}$ is

• A. $Y^{-}{Z}^{-}{X}^{-}$
• B. $Z^{-},X^{-},Y^{-}$
• C. $Y^{-},X^{-},Z^{-}$
• D. $X^{-},Z^{-},Y^{-}$

Answer 1

Answer: (A)

Since $TX$ does not react with any of the solutions, it means that $X$ is least easily oxidized.
Since $TY$ reacts with both $X$ and $Z$, i.e,,
$Y^{-}+X\to X^{-}+Y$ and $Y^{-}+Z\to Z^{-}+Y$,
therefore, $Y^{-}$ is most easily oxidized.
Since $TZ$ reacts with only $X$, i.e.
$Z^{-}+X\to X^{-}+Z$, therefore,
$Z^{-}$ is more easily oxidized than $X^{-}$ Combining all the results, the decreasing order of oxidation of anions follows the order
$Y^{-}>Z^{-}>X^{-}$