Question

Small quantities of solution of compounds $TX, TY$ and $TZ$ are put into separate test tubes containing $X, Y$ and $Z$ solution. $TX$ does not react with any of these. $TY$ reacts both with $X$ and $Z. TZ$ reacts with $X$. The decreasing order of ease of oxidation of the anions $X^-$, $Y^-$ and $Z^-$ is

• A. $Y^-Z^-X^-$
• B. $Z^-,X^- ,Y^-$
• C. $Y^- , X^- , Z^-$
• D. $X^- , Z^- , Y^-$

Answer 1

Answer: (A)

Since $TX$ does not react with any of the solutions, it means that $X$ is least easily oxidized.
Since $TY$ reacts with both $X$ and $Z$, i.e,,
$Y^- + X \rightarrow X^- + Y$ and $Y^- + Z \rightarrow Z^- + Y$,
therefore, $Y^-$ is most easily oxidized.
Since $TZ$ reacts with only $X$, i.e.
$ Z^- + X \rightarrow X^- + Z$, therefore,
$ Z^-$ is more easily oxidized than $X^-$ Combining all the results, the decreasing order of oxidation of anions follows the order
$Y^{-} > Z^{-} > X^{-} $