Six identical balls are randomly dropped into three boxes A, B, C which can hold any number of balls. If the probability that one of the box contain 1 and the other two contains 2 and 3 balls is expressed as ( p / q ) in lowest rational. Find ( p + q ).

Question

Six identical balls are randomly dropped into three boxes A, B, C which can hold any number of balls. If the probability that one of the box contain 1 and the other two contains 2 and 3 balls is expressed as ( p / q ) in lowest rational. Find ( p + q ). (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

n ( A )=3 !=6 (123,132,231,213,312,321) n ( S )= no. of ways the ball can be placed in A, B, C

Q. Six identical balls are randomly dropped into three boxes A, B, C which can hold any number of balls. If the probability that one of the box contain 1 and the other two contains 2 and 3 balls is expressed as $\frac{p}{q}$ in lowest rational. Find $(p + q)$ .

$n (A) = 3! = 6 (123, 132, 231, 213, 312, 321)$
$n (S) =$ no. of ways the ball can be placed in A, B, C

Q. Six identical balls are randomly dropped into three boxes A, B, C which can hold any number of balls. If the probability that one of the box contain 1 and the other two contains 2 and 3 balls is expressed as qp​ in lowest rational. Find (p+q).

n(A)=3!=6(123,132,231,213,312,321) n(S)= no. of ways the ball can be placed in A, B, C

Q. Six identical balls are randomly dropped into three boxes A, B, C which can hold any number of balls. If the probability that one of the box contain 1 and the other two contains 2 and 3 balls is expressed as $\frac{p}{q}$ in lowest rational. Find $(p + q)$ .

$n (A) = 3! = 6 (123, 132, 231, 213, 312, 321)$
$n (S) =$ no. of ways the ball can be placed in A, B, C