Q. Six identical balls are randomly dropped into three boxes A, B, C which can hold any number of balls. If the probability that one of the box contain 1 and the other two contains 2 and 3 balls is expressed as $\frac{ p }{ q }$ in lowest rational. Find $( p + q )$.
Probability - Part 2
Solution:
$n ( A )=3 !=6 \quad(123,132,231,213,312,321)$
$n ( S )=$ no. of ways the ball can be placed in A, B, C
