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Tardigrade
Question
Mathematics
sin-1 ( (√3/2)) - Tan-1 (- √3 ) =
Q.
sin
−
1
(
2
3
)
−
T
a
n
−
1
(
−
3
)
=
3640
211
Inverse Trigonometric Functions
Report Error
A
−
π
/3
23%
B
2
π
/3
47%
C
π
/6
15%
D
0
14%
Solution:
sin
−
1
(
2
3
)
−
tan
−
1
(
−
3
)
=
3
π
−
(
−
3
π
)
=
3
2
π