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  4. sin-1 ( (√3/2)) - Tan-1 (- √3 ) =

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Q. $\sin^{-1} ( \frac{\sqrt{3}}{2}) - Tan^{-1} (- \sqrt{3} ) = $

Inverse Trigonometric Functions

Solution:

$\sin^{-1} \left(\frac{\sqrt{3}}{2}\right) - \tan^{-1} \left( - \sqrt{3} \right) = \frac{\pi}{3} - \left(-\frac{\pi}{3}\right) = \frac{2\pi}{3 }$