SiCl4 on hydrolysis forms 'X' and HCl. Compound 'X' loses water at 1000° C and gives 'Y'. Compounds 'X' and 'Y' respectively

Question

SiCl4 on hydrolysis forms 'X' and HCl. Compound 'X' loses water at 1000° C and gives 'Y'. Compounds 'X' and 'Y' respectively (A)  H2SiCl6, SiO2 (B) H4SiO4, Si  (C) SiO2, Si  (D)  H4SiO4, SiO2

Tardigrade Admin · Accepted Answer

SiCl 4+4 H 2 O longrightarrow H 4 SiO 4+4 HCl H 4 SiO 4 xrightarrow[1000°C]Δ SiO 2+2 H 2 O

Q. $S i C l_{4}$ on hydrolysis forms ' $X$ ' and $H Cl$ . Compound ' $X$ ' loses water at $100 0^{\circ} C$ and gives ' $Y$ '. Compounds ' $X$ ' and ' $Y$ ' respectively

$H_{2} S i C l_{6}, S i O_{2}$

$H_{4} S i O_{4}, S i$

$S i O_{2}, S i$

$H_{4} S i O_{4}, S i O_{2}$

$S i C l_{4} + 4 H_{2} O ⟶ H_{4} S i O_{4} + 4 H Cl$
$H_{4} S i O_{4} Δ 100 0^{\circ} C S i O_{2} + 2 H_{2} O$

Q. SiCl4​ on hydrolysis forms 'X' and HCl. Compound 'X' loses water at 1000∘C and gives 'Y'. Compounds 'X' and 'Y' respectively

H2​SiCl6​,SiO2​

H4​SiO4​,Si

SiO2​,Si

H4​SiO4​,SiO2​