Show that each diagonal of a parallelogram divide it into two congruent triangles. The following are the steps involved in showing the above result. Arrange them in sequential order. (A) In triangle A B C and triangle C D A, A B=D C and B C=A D(∵ opposite angles of parallelogram) A C=A C (common side). (B) Let A B C D be a parallelogram. Join A C. (C) By SSS congruence property, triangle A B C ≅ triangle C D A. (D) Similarly, B D divides the triangle into two congruent triangles.

Question

Show that each diagonal of a parallelogram divide it into two congruent triangles. The following are the steps involved in showing the above result. Arrange them in sequential order. (A) In triangle A B C and triangle C D A, A B=D C and B C=A D(∵ opposite angles of parallelogram) A C=A C (common side). (B) Let A B C D be a parallelogram. Join A C. (C) By SSS congruence property, triangle A B C ≅ triangle C D A. (D) Similarly, B D divides the triangle into two congruent triangles. (A) BACD (B) BDAC (C) BADC (D) BDCA

Tardigrade Admin · Accepted Answer

BACD is the required sequential order.

$B A C D$

$B D A C$

$B A D C$

BDCA

$B A C D$ is the required sequential order.