Q. Show that each diagonal of a parallelogram divide it into two congruent triangles. The following are the steps involved in showing the above result. Arrange them in sequential order. (A) In $\triangle A B C$ and $\triangle C D A, A B=D C$ and $B C=A D(\because$ opposite angles of parallelogram) $A C=A C$ (common side). (B) Let $A B C D$ be a parallelogram. Join $A C$. (C) By SSS congruence property, $\triangle A B C \cong \triangle C D A$. (D) Similarly, $B D$ divides the triangle into two congruent triangles.
Geometry
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