Shaft of a motor rotates at a constant angular velocity of 3000 rpm. The radians it has turned through in 1 s is

Question

Shaft of a motor rotates at a constant angular velocity of 3000 rpm. The radians it has turned through in 1 s is (A)  π  (B)  10π  (C)  50π  (D)  100π

Tardigrade Admin · Accepted Answer

Given, ω=3000 rpm For rotation per second, we have ω =(3000/60) rps =50 rps =50 × 2 π rad / s =100 π rad / s ∴ θ =ω t =100 π rad

Q. Shaft of a motor rotates at a constant angular velocity of $3000 r p m$ . The radians it has turned through in $1 s$ is

$π$

$10 π$

$50 π$

$100 π$

Given, $ω = 3000 r p m$
For rotation per second, we have
$< b r / >< b r / > ω = \frac{3000}{60} r p s = 50 r p s = 50 \times 2 π r a d / s < b r / >= 100 π r a d / s < b r / > ∴ θ = ω t = 100 π r a d < b r / >< b r / >$

Q. Shaft of a motor rotates at a constant angular velocity of 3000rpm. The radians it has turned through in 1s is

π

10π

50π

100π

Given, ω=3000rpm For rotation per second, we have <br/><br/>ω=603000​rps=50rps=50×2πrad/s<br/>=100πrad/s<br/>∴θ=ωt=100πrad<br/><br/>

Q. Shaft of a motor rotates at a constant angular velocity of $3000 r p m$ . The radians it has turned through in $1 s$ is

$π$

$10 π$

$50 π$

$100 π$

Given, $ω = 3000 r p m$
For rotation per second, we have
$< b r / >< b r / > ω = \frac{3000}{60} r p s = 50 r p s = 50 \times 2 π r a d / s < b r / >= 100 π r a d / s < b r / > ∴ θ = ω t = 100 π r a d < b r / >< b r / >$