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Q. Shaft of a motor rotates at a constant angular velocity of $3000\, rpm$. The radians it has turned through in $1\, s$ is

Bihar CECEBihar CECE 2014System of Particles and Rotational Motion

Solution:

Given, $\omega=3000 rpm$
For rotation per second, we have
$

\omega =\frac{3000}{60} rps =50 rps =50 \times 2 \pi rad / s \\
=100 \pi rad / s \\
\therefore \theta =\omega t =100 \pi rad

$