Question

Select transition metal ions, the one where all metal ions have $3d^2$ electronic configuration :
[ Atomic nos. $Ti=22,V=23,Cr=24,Mn=25$ ]

• A. $T{i}^{3+},V^{2+},C{r}^{3+},M{n}^{4+}$
• B. $T{i}^{+},V^{4+},C{r}^{6+},M{n}^{7+}$
• C. $T{i}^{4+},V^{3+},C{r}^{2+},M{n}^{3+}$
• D. $T{i}^{2+},V^{3+},C{r}^{4+},M{n}^{5+}$

Answer 1

Answer: (D)

Ti₂₂ = 3d² 4s² ; Ti²⁺ = 3d²
V₂₃ = 3d³ 4s² ; V³⁺ = 3d²
Cr₂₄ = 3d⁴ 4s² ; Cr⁴⁺ = 3d²
Mn₂₅ = 3d⁵ 4s² ; Mn⁵⁺ = 3d²