Question

Select transition metal ions, the one where all metal ions have $3d^{2}$ electronic configuration :
[ Atomic nos. $Ti=22,V=23,Cr=24,Mn=25$ ]

• A. $Ti^{3 +},V^{2 +},Cr^{3 +},Mn^{4 +}$
• B. $Ti^{+},V^{4 +},Cr^{6 +},Mn^{7 +}$
• C. $Ti^{4 +},V^{3 +},Cr^{2 +},Mn^{3 +}$
• D. $Ti^{2 +},V^{3 +},Cr^{4 +},Mn^{5 +}$

Answer 1

Answer: (D)

Ti₂₂ = 3d² 4s² ; Ti²⁺ = 3d²
V₂₃ = 3d³ 4s² ; V³⁺ = 3d²
Cr₂₄ = 3d⁴ 4s² ; Cr⁴⁺ = 3d²
Mn₂₅ = 3d⁵ 4s² ; Mn⁵⁺ = 3d²