Question

Select the correct option, among $Sc(III)$, $Ti(IV)$, $Pd(II)$ and $Cu(II)$ ions

• A. all are paramagnetic
• B. all are diamagnetic
• C. $Sc(III)$, $Ti(IV)$ are paramagnetic and $Pd(III)$, $Cu(Il)$ are diamagnetic
• D. $Sc(III)$, $Ti(IV)$ are diamagnetic and $Pd(II)$, $Cu(II)$ are paramagnetic

Answer 1

Answer: (D)

$S{C}^{3+}\left([Ar]3d^0\right)]\to$ since no unpaired electrons so diamagnetic
$T{i}^{4+}\left([Ar]3d^0\right)]\to$ since no unpaired electrons so diamagnetic
$P{d}^{2+}\left([Kr]4d^8\right)]\to$ since there is unpaired electrons so paramagnetic
$C{u}^{2+}\left([Ar]3d^9\right)]\to$ since there is unpaired electrons so paramagnetic.