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Q.
Select the correct option, among $Sc(III)$, $Ti(IV)$, $Pd(II)$ and $Cu(II)$ ions
The d-and f-Block Elements
Solution:
$\left.SC ^{3+}\left([ Ar ] 3 d ^{0}\right)\right] \rightarrow$ since no unpaired electrons so diamagnetic
$\left.Ti ^{4+}\left([ Ar ] 3 d ^{0}\right) \right] \rightarrow$ since no unpaired electrons so diamagnetic
$\left.Pd ^{2+}\left([ Kr ] 4 d ^{8}\right)\right] \rightarrow$ since there is unpaired electrons so paramagnetic
$\left.Cu ^{2+}\left([ Ar ] 3 d ^{9}\right)\right] \rightarrow$ since there is unpaired electrons so paramagnetic.