Scale on a particular travelling microscope has 50 vernier scale divisions which coincide with 49 main scale divisions. It is known that each main scale division is 0.5mm , then figure out the least count of the microscope.

Question

Scale on a particular travelling microscope has 50 vernier scale divisions which coincide with 49 main scale divisions. It is known that each main scale division is 0.5mm , then figure out the least count of the microscope. (A) 0.01cm (B) 0.5mm (C) 0.01mm (D) 0.5cm

Tardigrade Admin · Accepted Answer

1 MSD =0.5 mm 50 VSD =49 MSD Least count = 1MSD - 1 VSD = 1MSD-(49/50)MSD=(1/50)× 0.5 mm=0.01mm

Q. Scale on a particular travelling microscope has $50$ vernier scale divisions which coincide with $49$ main scale divisions. It is known that each main scale division is $0.5 mm$ , then figure out the least count of the microscope.

$0.01 c m$

$0.5 mm$

$0.01 mm$

$0.5 c m$

$1 MS D = 0.5 mm$
$50 V S D = 49 MS D$
Least count $= 1 MS D - 1 V S D$
= $1 MS D - \frac{49}{50} MS D = \frac{1}{50} \times 0.5 mm = 0.01 mm$

Q. Scale on a particular travelling microscope has 50 vernier scale divisions which coincide with 49 main scale divisions. It is known that each main scale division is 0.5mm , then figure out the least count of the microscope.

0.01cm

0.5mm

0.01mm

0.5cm