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Q. Scale on a particular travelling microscope has $50$ vernier scale divisions which coincide with $49$ main scale divisions. It is known that each main scale division is $0.5mm$ , then figure out the least count of the microscope.

NTA AbhyasNTA Abhyas 2020

Solution:

$1 \, MSD \, =0.5 \, mm$
$50 \, VSD \, =49 \, MSD$
Least count $= \, 1MSD \, - \, 1 \, VSD$
= $1MSD-\frac{49}{50}MSD=\frac{1}{50}\times 0.5 \, mm=0.01mm$