Question

$Sb{F}_5$ reacts with $Xe{F}_4$ to form an adduct. The shapes of cation and anion in the adduct are respectively.

• A. square planar, trigonal bipyramidal
• B. T-shaped, octahedral
• C. square pyramidal, octahedral
• D. square planar, octahedral

Answer 1

Answer: (B)

${\text{SbF}}_5+{\text{XeF}}_4\to {\underset{\text{T}-\text{shaped}}{\left[{\text{XeF}}_3\right]}}^{+}+{\underset{\text{octahedral}}{\left[{\text{SbF}}_6\right]}}^{-}$