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  4. SbF5 reacts with XeF4 to form an adduct. The shapes of cation and anion in the adduct are respectively.

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Q. $SbF_{5}$ reacts with $XeF_{4}$ to form an adduct. The shapes of cation and anion in the adduct are respectively.

NTA AbhyasNTA Abhyas 2020The p-Block Elements - Part2

Solution:

$\text{SbF}_{5} + \text{XeF}_{4} \rightarrow \underset{\text{T} - \text{shaped}}{\left[\text{XeF}_{3}\right]}^{+} + \underset{\text{octahedral}}{\left[\text{SbF}_{6}\right]}^{-}$