Question

$Sb{F}_3$ reacts with $Xe{F}_4$ and $Xe{F}_6$ to form ionic compounds $\left[Xe{F}_3^{+}\right]\left[Sb{F}_6^{-}\right]$ and $\left[Xe{F}_5^{+}\right]\left[Sb{F}_6^{-}\right]$ then molecular shape of $\left[Xe{F}_3^{+}\right]$ ion and $\left[Xe{F}_5^{+}\right]$ ion respectively

• A. Square pyramidal, T-shaped
• B. Bent-T-shape, square pyramidal
• C. See-saw, square pyramidal
• D. Square pyramidal, See-saw

Answer 1

Answer: (B)

The shapes of these ions are as follows

$[Xe{F}_3^{+}]:$ Bent-T shape ( $s{p}^{3}d$ -hybridisation)

$[Xe{F}_5^{+}]:$ Square pyramidal ( $s{p}^3{d}^2$ -hybridisation)