Question

Roots of the equation $x^2+bx-c=0(b,c>0)$ are

• A. Both positive
• B. Both negative
• C. Of opposite sign
• D. None of these

Answer 1

Answer: (C)

Since $b,c>0$
Therefore $a+b=-b<0$ and $ab=-c<0$
Since product of the roots is -ve therefore roots must be of opposite sign.