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  4. Roots of the equation x2 + bx - c = 0(b,c > 0) are

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Q. Roots of the equation $x^2 + bx - c = 0(b,c > 0)$ are

BITSATBITSAT 2018

Solution:

Since $b, c > 0$
Therefore $a + b = -b < 0$ and $a b = -c < 0 $
Since product of the roots is -ve therefore roots must be of opposite sign.