Ring structure of glucose is due to the formation of hemiacetal and ring formation between

Question

Ring structure of glucose is due to the formation of hemiacetal and ring formation between (A) C 1 and C 5 (B) C1 and C4 (C) C 1 and C 3 (D) C 2 and C 4

Tardigrade Admin · Accepted Answer

Pyranose ring structure of glucose is due to hemiacetal formation between C 1 and C 5 carbon atoms. In general, a pyranose is any cyclic isomer that has a five carbon atoms and one oxygen atom in a ring of six atoms. If a hydroxyl at the 5 position of an aldohexose, such as glucose, forms a hemiacetal with the aldehyde (position 1), the resulting isomer is glucopyranose.

Q. Ring structure of glucose is due to the formation of hemiacetal and ring formation between

$C_{1}$ and $C_{5}$

$C_{1}$ and $C_{4}$

$C_{1}$ and $C_{3}$

$C_{2}$ and $C_{4}$

Q. Ring structure of glucose is due to the formation of hemiacetal and ring formation between

C1​ and C5​

C1​ and C4​

C1​ and C3​

C2​ and C4​

$C_{1}$ and $C_{5}$

$C_{1}$ and $C_{4}$

$C_{1}$ and $C_{3}$

$C_{2}$ and $C_{4}$