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  4. Ring structure of glucose is due to the formation of hemiacetal and ring formation between

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Q. Ring structure of glucose is due to the formation of hemiacetal and ring formation between

Biomolecules

Solution:

Pyranose ring structure of glucose is due to hemiacetal formation between $C _{1}$ and $C _{5}$ carbon atoms. In general, a pyranose is any cyclic isomer that has a five carbon atoms and one oxygen atom in a ring of six atoms. If a hydroxyl at the 5 position of an aldohexose, such as glucose, forms a hemiacetal with the aldehyde (position 1), the resulting isomer is glucopyranose.