Question

Required amount of crystalline oxalic acid (eq. $\text{w}\text{t}.=63$ ) to prepare $\frac{\text{N}}{10},$ $250\text{m}\text{l}$ oxalic acid solution is

• A. $0.158\text{g}$
• B. $1.575\text{g}$
• C. $15.75\text{g}$
• D. $6.3\text{g}$

Answer 1

Answer: (B)

$\text{N}=\frac{{\text{W}}_{\text{B}}\times 1000}{\text{E}\times \text{V}}\Rightarrow \frac{\text{N}}{10}=\frac{\text{x}\times 1000}{63\times 250}$

Where, W_B is the weight of sample, E is the equivalent weight of substance and V is volume of solution.

$\therefore$ $\text{x}=1.575\text{g}\text{r}\text{a}\text{m}\text{s}$