Question

Required amount of crystalline oxalic acid (eq. $\text{w}\text{t}.=63$ ) to prepare $\frac{\text{N}}{10},$ $250 \, \text{m}\text{l}$ oxalic acid solution is

• A. $0.158 \, \text{g}$
• B. $1.575 \, \text{g}$
• C. $15.75 \, \text{g}$
• D. $6.3 \, \text{g}$

Answer 1

Answer: (B)

$\text{N} \, = \, \frac{\text{W}_{\text{B}} \, \times \, 1000}{\text{E} \, \times \, \text{V}}\Rightarrow \, \frac{\text{N}}{10} \, = \, \frac{\text{x} \, \times \, 1000}{63 \, \times \, 250}$

Where, W_B is the weight of sample, E is the equivalent weight of substance and V is volume of solution.

$\therefore $ $\text{x}=1.575 \, \text{g}\text{r}\text{a}\text{m}\text{s}$