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Physics
Relation between the ratio of specific heats (γ) of gas and degree of freedom ' f ' will be
Q. Relation between the ratio of specific heats
(
γ
)
of gas and degree of freedom '
f
' will be
1789
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A
γ
=
f
+
2
B
γ
1
=
f
1
+
2
1
C
f
=
γ
−
1
2
D
f
=
2
(
γ
−
1
)
Solution:
γ
=
C
V
C
P
=
C
V
C
V
+
R
=
2
1
f
R
2
1
f
R
+
R
=
f
f
+
2
⇒
γ
f
−
f
=
2
⇒
f
=
γ
−
1
2