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Q. Relation between the ratio of specific heats $(\gamma)$ of gas and degree of freedom ' $f$ ' will be

Solution:

$\gamma=\frac{ C _{ P }}{ C _{ V }}=\frac{ C _{ V }+ R }{ C _{ V }} $
$=\frac{\frac{1}{2} fR + R }{\frac{1}{2} fR }=\frac{ f +2}{ f }$
$\Rightarrow \gamma f - f =2$
$ \Rightarrow f =\frac{2}{\gamma-1}$