Red hot carbon will remove oxygen from the oxide A O and B O but not from M O, while B will remove oxygen from A O. The activity of metals A, B and M in decreasing order is

Question

Red hot carbon will remove oxygen from the oxide A O and B O but not from M O, while B will remove oxygen from A O. The activity of metals A, B and M in decreasing order is (A) A > B > M (B) B > A > M (C) M > B > A (D) M > A > B

Tardigrade Admin · Accepted Answer

Carbon removes oxygen from A O and B O, C is better reducing agent than A and B ; B removes oxygen from A O, B is better reducing agent than A. Better reducing means more active. Hence, the correct order is M> C >B>A

Q. Red hot carbon will remove oxygen from the oxide $A O$ and $BO$ but not from $MO,$ while $B$ will remove oxygen from $A$ O. The activity of metals $A, B$ and $M$ in decreasing order is

$A > B > M$

$B > A > M$

$M > B > A$

$M > A > B$

Carbon removes oxygen from $A O$ and $BO, C$ is better reducing agent than $A$ and $B; B$ removes oxygen from $A O, B$ is better reducing agent than $A$ . Better reducing means more active. Hence, the correct order is $M > C > B > A$

Q. Red hot carbon will remove oxygen from the oxide AO and BO but not from MO, while B will remove oxygen from A O. The activity of metals A,B and M in decreasing order is

A>B>M

B>A>M

M>B>A

M>A>B