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Q. Red hot carbon will remove oxygen from the oxide $A O$ and $B O$ but not from $M O,$ while $B$ will remove oxygen from $A$ O. The activity of metals $A, B$ and $M$ in decreasing order is

Electrochemistry

Solution:

Carbon removes oxygen from $A O$ and $B O, C$ is better reducing agent than $A$ and $B ; B$ removes oxygen from $A O, B$ is better reducing agent than $A$. Better reducing means more active. Hence, the correct order is $M> C >B>A$