Reaction coordinate diagram for the reaction COCl 2( g ) longrightarrow CO ( g )+ Cl 2( g ), Δ H =103.1 kJ with log k ( min -1)=(-11420/T)+15.154 is

Question

Reaction coordinate diagram for the reaction COCl 2( g ) longrightarrow CO ( g )+ Cl 2( g ), Δ H =103.1 kJ with log k ( min -1)=(-11420/T)+15.154 is (A)  (B)  (C) Both (a) and (b) (D) None o f these

Tardigrade Admin · Accepted Answer

By Arrhenius equation log 10 k =-(Ea/2.303 R T)+ log A ∴ (Ea/2.303)=11420 K ∴ Ea=11420 × 2.303 × R K =11420 × 2.303 × 8.314 × 10-3 kJ mol K -1 K =218.67 kJ mol -1 Given reaction is endothermic, Δ H =+103.1 kJ Thus, reaction-coordinate diagram is <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/4a8ccb74e31daee55ddbde026aefbe22-.png" />

Q. Reaction coordinate diagram for the reaction COCl2​(g)⟶CO(g)+Cl2​(g),ΔH=103.1kJ with logk(min−1)=T−11420​+15.154 is

Both (a) and (b)

None o f these

By Arrhenius equation log10​k=−2.303RTEa​​+logA ∴2.303Ea​​=11420K ∴Ea​=11420×2.303×RK =11420×2.303×8.314×10−3kJmolK−1K =218.67kJmol−1 Given reaction is endothermic, ΔH=+103.1kJ Thus, reaction-coordinate diagram is

Q. Reaction coordinate diagram for the reaction
$COC l_{2} (g) ⟶ CO (g) + C l_{2} (g), Δ H = 103.1 k J$
with $lo g k (min^{- 1}) = \frac{- 11420}{T} + 15.154$ is