Ratio of number of oxygen atoms in Ca3(PO4)2 and H3PO3, if both contain same number of P atoms, is

Question

Ratio of number of oxygen atoms in Ca3(PO4)2 and H3PO3, if both contain same number of P atoms, is (A) 3: 4 (B) 4: 3 (C) 2: 3 (D) 3: 2

Tardigrade Admin · Accepted Answer

1 molecule of Ca3(PO4)2 contains 2 atoms, of P and 1 molecule of H3PO3 contains 1 atom of P. So, 0.5 molecule of Ca3(PO4)2 and 1 molecule of H3PO3 contain equal number of P atoms. Number of oxygen atoms in 0.5 molecule of Ca3(PO4)2 = 0.5 × 8 = 4 And in 1 molecule H3PO3 = 3

Q. Ratio of number of oxygen atoms in $C a_{3} (P O_{4})_{2}$ and $H_{3} P O_{3}$ , if both contain same number of $P$ atoms, is

$3 : 4$

$4 : 3$

$2 : 3$

$3 : 2$

Q. Ratio of number of oxygen atoms in Ca3​(PO4​)2​ and H3​PO3​, if both contain same number of P atoms, is

3:4

4:3

2:3

3:2

Q. Ratio of number of oxygen atoms in $C a_{3} (P O_{4})_{2}$ and $H_{3} P O_{3}$ , if both contain same number of $P$ atoms, is

$3 : 4$

$4 : 3$

$2 : 3$

$3 : 2$