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  4. Ratio of number of oxygen atoms in Ca3(PO4)2 and H3PO3, if both contain same number of P atoms, is

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Q. Ratio of number of oxygen atoms in $Ca_3(PO_4)_2$ and $H_3PO_3$, if both contain same number of $P$ atoms, is

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Solution:

$1$ molecule of $Ca_3(PO_4)_2$ contains $2$ atoms, of $P$ and $1$ molecule of $H_3PO_3$ contains $1$ atom of $P$.
So, $0.5$ molecule of $Ca_3(PO_4)_2$ and $1$ molecule of $H_3PO_3$ contain equal number of $P$ atoms.
Number of oxygen atoms in
$0.5$ molecule of $Ca_3(PO_4)_2 = 0.5 \times 8 = 4$
And in $1$ molecule $H_3PO_3 = 3$