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Question
Chemistry
Rate of effusion of LPG (a mixture of n-butanemole fraction of n-butane in LPG is
Q. Rate of effusion of LPG (a mixture of n-butanemole fraction of n-butane in LPG is
1470
155
States of Matter
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A
0.75
16%
B
0.25
30%
C
0.50
41%
D
0.67
13%
Solution:
r
2
/
r
1
= 1.25
M
2
=
?
.
M
1
= 32 + 16
×
3 = 80
r
1
r
2
=
M
2
M
1
; 1.25 =
M
2
80
M
2
=
25
80
×
16
=
25
1280
=51.2
Mol mass of
C
4
H
18
= 58
Mol mass of
C
3
H
8
= 44
Let mole fraction of
C
4
H
10
= x
∴
58x + 44(1 -x ) = 51.2
58r - 44x = 51.2 - 44.0
14x = 7.2
x
=
15
7.2
=
0.5