Rain is falling vertically with a speed of 12 ms-1. A woman rides a bicycles with a speed of 12 ms-1 in east to west direction. What is the direction in which she should hold her umbrella?

Question

Rain is falling vertically with a speed of 12 ms-1. A woman rides a bicycles with a speed of 12 ms-1 in east to west direction. What is the direction in which she should hold her umbrella? (A) 30° towards East (B) 45° towards East (C) 30° towards West (D) 45° towards West

Tardigrade Admin · Accepted Answer

To protect herself from the rain, the woman must hold her umbrella in the direction of the relative velocity of the rain with respect to the woman.

tan θ = v_{w} / v_{f} = 12 m / s

or,

tan θ = 1

or,

θ = 4 5^{\circ}

Therefore, the direction in which she should hold her umbrella is

4 5^{\circ}

toward west.

Q. Rain is falling vertically with a speed of $12 m s^{- 1}$ . A woman rides a bicycles with a speed of $12 m s^{- 1}$ in east to west direction. What is the direction in which she should hold her umbrella?

$3 0^{\circ}$ towards East

$4 5^{\circ}$ towards East

$3 0^{\circ}$ towards West

$4 5^{\circ}$ towards West

Q. Rain is falling vertically with a speed of 12ms−1. A woman rides a bicycles with a speed of 12ms−1 in east to west direction. What is the direction in which she should hold her umbrella?

30∘ towards East

45∘ towards East

30∘ towards West

45∘ towards West

To protect herself from the rain, the woman must hold her umbrella in the direction of the relative velocity of the rain with respect to the woman. tanθ=vw​/vf​=12m/s or, tanθ=1 or, θ=45∘ Therefore, the direction in which she should hold her umbrella is 45∘ toward west.

Q. Rain is falling vertically with a speed of $12 m s^{- 1}$ . A woman rides a bicycles with a speed of $12 m s^{- 1}$ in east to west direction. What is the direction in which she should hold her umbrella?

$3 0^{\circ}$ towards East

$4 5^{\circ}$ towards East

$3 0^{\circ}$ towards West

$4 5^{\circ}$ towards West