Radioactive element decays to form a stable nuclide, then the rate of decay of reactant is shown by

Question

Radioactive element decays to form a stable nuclide, then the rate of decay of reactant is shown by (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

No. of nuclide at time t is given by N=Noe-λ t Where, No = initial nuclide Thus this equation is equivalent to y=ae-kx So correct graph is in option (c)

Q. Radioactive element decays to form a stable nuclide, then the rate of decay of reactant is shown by

No. of nuclide at time t is given by
$N = N_{o} e^{- λ t}$
Where, $N_{o} =$ initial nuclide
Thus this equation is equivalent to
$y = a e^{- k x}$
So correct graph is in option (c)

Q. Radioactive element decays to form a stable nuclide, then the rate of decay of reactant is shown by

No. of nuclide at time t is given by N=No​e−λt Where, No​= initial nuclide Thus this equation is equivalent to y=ae−kx So correct graph is in option (c)

No. of nuclide at time t is given by
$N = N_{o} e^{- λ t}$
Where, $N_{o} =$ initial nuclide
Thus this equation is equivalent to
$y = a e^{- k x}$
So correct graph is in option (c)