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  4. Radioactive element decays to form a stable nuclide, then the rate of decay of reactant is shown by

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Q. Radioactive element decays to form a stable nuclide, then the rate of decay of reactant is shown by

VITEEEVITEEE 2019

Solution:

No. of nuclide at time t is given by
$N=N_{o}e^{-\lambda t}$
Where, $N_{o} =$ initial nuclide
Thus this equation is equivalent to
$y=ae^{-kx}$
So correct graph is in option (c)

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