Question

Principle product $(X)$ in the reaction $C{H}_{3}CON{H}_2\underset{B{r}_2+NaOH}{\to }X$ is:

• A. $C{H}_{3}COOH$
• B. $C{H}_{3}N{H}_2$
• C. $C{H}_{3}Br$
• D. $C{H}_{3}C{H}_{2}N{H}_2$

Answer 1

Answer: (B)

This is Hofmann bromamide reaction. In this reaction acid amide reacts with bromine and KOH (or $NaOH$ ) to form amine having one carbon atom less than acid amide
$\underset{\text{acetamide}}{C{H}_{3}CON{H}_2}+B{r}_2+4KOH\to \underset{(X)\text{methylamine}}{C{H}_{3}N{H}_2}$
$+2KBr+K_{2}C{O}_3+2H_{2}O$
$\therefore$ The principle product $X$ in the reaction is methyl amine.