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Q.
Principle product $(X)$ in the reaction $ CH_{3}CONH_{2}\xrightarrow[Br_{2}+NaOH]{}X $ is:
Delhi UMET/DPMTDelhi UMET/DPMT 2002
Solution:
This is Hofmann bromamide reaction. In this reaction acid amide reacts with bromine and KOH (or $NaOH$ ) to form amine having one carbon atom less than acid amide
$\underset{\text{acetamide}}{CH _{3} CONH _{2}}+ Br _{2}+4 KOH \rightarrow \underset{(X)\text{methylamine}}{CH _{3} NH _{2}}$
$+2 KBr + K _{2} CO _{3}+2 H _{2} O$
$\therefore $ The principle product $X$ in the reaction is methyl amine.