Pressure versus temperature graph of an ideal gas is as shown in figure. Density of the gas at point A is ρ 0 . Density at point B will be :-

Question

Pressure versus temperature graph of an ideal gas is as shown in figure. Density of the gas at point A is ρ 0 . Density at point B will be :- <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-xu8e1rhdneuevn8q.jpg" /> (A) (3/4)ρ 0 (B) (3/2)ρ 0 (C) (4/3)ρ 0 (D) 2ρ 0

Tardigrade Admin · Accepted Answer

(P/ρ )=(R T/MW) ρ =(P MW/R T) ρ propto (P/T) ρ A=ρ 0=(P0/ T0) ⇒ ρ B=(3 P0/2 T0)=(3/2)ρ 0

Q. Pressure versus temperature graph of an ideal gas is as shown in figure. Density of the gas at point $A$ is $ρ_{0}$ . Density at point $B$ will be :-

$\frac{3}{4} ρ_{0}$

$\frac{3}{2} ρ_{0}$

$\frac{4}{3} ρ_{0}$

$2 ρ_{0}$

$\frac{P}{ρ} = \frac{RT}{M _{W}}$
$ρ = \frac{P M _{W}}{RT}$
$ρ \propto \frac{P}{T}$
$ρ_{A} = ρ_{0} = \frac{P _{0}}{T _{0}}$
$\Rightarrow ρ_{B} = \frac{3 P _{0}}{2 T _{0}} = \frac{3}{2} ρ_{0}$

Q. Pressure versus temperature graph of an ideal gas is as shown in figure. Density of the gas at point A is ρ0​ . Density at point B will be :-

43​ρ0​

23​ρ0​

34​ρ0​

2ρ0​