Question

Pressure versus temperature graph of an ideal gas is as shown in figure. Density of the gas at point $A$ is $\rho _{0}$ . Density at point $B$ will be :-

• A. $\frac{3}{4}\rho _{0}$
• B. $\frac{3}{2}\rho _{0}$
• C. $\frac{4}{3}\rho _{0}$
• D. $2\rho _{0}$

Answer 1

Answer: (B)

$\frac{P}{\rho }=\frac{R T}{M_{W}}$
$\rho =\frac{P M_{W}}{R T}$
$\rho \propto \frac{P}{T}$
$\rho _{A}=\rho _{0}=\frac{P_{0}}{ T_{0}}$
$\Rightarrow \rho _{B}=\frac{3 P_{0}}{2 T_{0}}=\frac{3}{2}\rho _{0}$