Question

Pressure versus temperature graph of an ideal gas is as shown in figure. Corresponding density $(\rho )$ versus volume $(V)$ graph will be

• A.
• B.
• C.
• D.

Answer 1

Answer: (B)

Process $AB$ is an isothermal process, i.e., $P\propto 1/V$ and since $\rho \propto 1/V,\rho -V$ graph will be a rectangular hyperbola. Pressure is increasing; therefore, volume will increase. Process $BC$ is an isochoric process. Therefore, $V=$ constant and since $\rho =m/V$, density is also constant, i.e., $\rho -V$ graph is a dot. Process $CD$ is inverse of process $AB$ and process $DA$ is inverse is $BC$.