Question

Pressure versus temperature graph of an ideal gas is as shown in figure. Corresponding density $(\rho)$ versus volume $(V)$ graph will be

• A.
• B.
• C.
• D.

Answer 1

Answer: (B)

Process $A B$ is an isothermal process, i.e., $P \propto 1 / V$ and since $\rho \propto 1 / V, \rho-V$ graph will be a rectangular hyperbola. Pressure is increasing; therefore, volume will increase. Process $B C$ is an isochoric process. Therefore, $V=$ constant and since $\rho=m / V$, density is also constant, i.e., $\rho-V$ graph is a dot. Process $C D$ is inverse of process $A B$ and process $D A$ is inverse is $B C$.