In order to arrive at the correct answer we solve for dimensional formula of each individually.
Pressure gradient =−ΔxΔP=mN/m2 ∴ Dimensions of (ΔxΔP)=[L][MLT−2]/[L2] =[ML−2T−2]
Dimension of velocity gradient =[−ΔxΔv]=mm/s=[L][LT−1] =[M0L0T−1]
Dimensions of potential gradient =(−ΔxΔV)ΔxΔW/Q=[AT][L][MLT−2][L] =[MLT−3A−1]
Energy gradient =−ΔxΔE=mNm
Dimensions of (ΔxΔE)=[L][MLT−2][L] =[MLT−2]
As observed from above results we see that none of the dimensions are same as of pressure gradient