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Q.
Pressure gradient has the same dimensions as that of:
AFMCAFMC 2004
Solution:
In order to arrive at the correct answer we solve for dimensional formula of each individually.
Pressure gradient =−ΔPΔx=N/m2m ∴ Dimensions of (ΔPΔx)=[MLT−2]/[L2][L] =[ML−2T−2]
Dimension of velocity gradient =[−ΔvΔx]=m/sm=[LT−1][L] =[M0L0T−1]
Dimensions of potential gradient =(−ΔVΔx)ΔW/QΔx=[MLT−2][L][AT][L] =[MLT−3A−1]
Energy gradient =−ΔEΔx=Nmm
Dimensions of (ΔEΔx)=[MLT−2][L][L] =[MLT−2]
As observed from above results we see that none of the dimensions are same as of pressure gradient