Points (t-1,2 t+2) and (2 t+1, t+1) are images of each other with respect of line 'L'. If ' L ' passes through (-1,0) then value of ' t ' is

Question

Points (t-1,2 t+2) and (2 t+1, t+1) are images of each other with respect of line 'L'. If ' L ' passes through (-1,0) then value of ' t ' is (A) (1/2) (B) (3/2) (C) (-3/2) (D) (-1/2)

Tardigrade Admin · Accepted Answer

AP = PB ⇒ √ t 2+(2 t +2)2=√(2 t +2)2+( t +1)2 or t =(-1/2)

Q. Points $(t - 1, 2 t + 2)$ and $(2 t + 1, t + 1)$ are images of each other with respect of line 'L'. If ' $L$ ' passes through $(- 1, 0)$ then value of ' $t$ ' is

$\frac{1}{2}$

$\frac{3}{2}$

$\frac{- 3}{2}$

$\frac{- 1}{2}$

$A P = PB$
$\Rightarrow t^{2} + (2 t + 2)^{2} = (2 t + 2)^{2} + (t + 1)^{2}$
or $t = \frac{- 1}{2}$

Q. Points (t−1,2t+2) and (2t+1,t+1) are images of each other with respect of line 'L'. If ' L ' passes through (−1,0) then value of ' t ' is

21​

23​

2−3​

2−1​