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Q. Points $(t-1,2 t+2)$ and $(2 t+1, t+1)$ are images of each other with respect of line 'L'. If ' $L$ ' passes through $(-1,0)$ then value of ' $t$ ' is

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Solution:

$AP = PB$
$\Rightarrow \sqrt{ t ^2+(2 t +2)^2}=\sqrt{(2 t +2)^2+( t +1)^2}$
or $t =\frac{-1}{2}$

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