Plutonium decays with half life of 24000 years. If plutonium is stored for 72000 years, the fraction of it that remains is

Question

Plutonium decays with half life of 24000 years. If plutonium is stored for 72000 years, the fraction of it that remains is (A) 1/8 (B) 1/3 (C) 1/4 (D) 1/2

Tardigrade Admin · Accepted Answer

Here, n=(72000/24000)=3, (N/N0)=((1/2))n=((1/2))3=(1/8)

Q. Plutonium decays with half life of $24000$ years. If plutonium is stored for $72000$ years, the fraction of it that remains is

$1/8$

$1/3$

$1/4$

$1/2$

Here, $n = \frac{72000}{24000} = 3, \frac{N}{N _{0}} = (\frac{1}{2})^{n} = (\frac{1}{2})^{3} = \frac{1}{8}$

Q. Plutonium decays with half life of 24000 years. If plutonium is stored for 72000 years, the fraction of it that remains is

1/8

1/3

1/4

1/2