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  4. Plutonium decays with half life of 24000 years. If plutonium is stored for 72000 years, the fraction of it that remains is

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Q. Plutonium decays with half life of $24000$ years. If plutonium is stored for $72000$ years, the fraction of it that remains is

Nuclei

Solution:

Here, $n=\frac{72000}{24000}=3, \frac{N}{N_{0}}=\left(\frac{1}{2}\right)^{n}=\left(\frac{1}{2}\right)^{3}=\frac{1}{8}$