Plates of a parallel plate capacitor, having a potential difference 100 V applied across them, carry a surface charge density of 50 nC cm- 2 . Spacing between the plates is

Question

Plates of a parallel plate capacitor, having a potential difference 100 V applied across them, carry a surface charge density of 50 nC cm- 2 . Spacing between the plates is (A) 329 μ m (B) 259 μ m (C) 177 μ m (D) 125 μ m

Tardigrade Admin · Accepted Answer

E=(σ /ϵ 0) Potential difference V=Ed ∴ d=(V/E)=(100/50 × 10- 7)× text8.85× 10- 12= text177× 10- 6m=177Î¼m

Q. Plates of a parallel plate capacitor, having a potential difference $100 V$ applied across them, carry a surface charge density of $50 n C c m^{- 2}$ . Spacing between the plates is

$329 μ m$

$259 μ m$

$177 μ m$

$125 μ m$

$E = \frac{σ}{ϵ _{0}}$
Potential difference $V = E d$
$∴ d = \frac{V}{E} = \frac{100}{50 \times 1 0 ^{- 7}} \times 8.85 \times 1 0^{- 12} = 177 \times 1 0^{- 6} m = 177 μ m$

Q. Plates of a parallel plate capacitor, having a potential difference 100V applied across them, carry a surface charge density of 50nCcm−2 . Spacing between the plates is

329μm

259μm

177μm

125μm